Reduced temperature and reduced volume of benzene are 0.7277 and 0.40 respectively Calculate reduced pressure of benzene .

Explanation

According to law of corresponding state
`[P_(r) + (3)/(V_(r)^(2))][3V_(r) -1]=8RT_(r)`
`[P_(r) + (3)/((0.4)^(2))][3 xx 0.4 -1]=8 xx 0.7277`
`P_(r) = 10.350` .