A manometer is connected to a gas containing bulb. The open arm reads `43.7 cm` whereas the arm connected to the bulb reads `15.6 cm`. If the barometric pressure is `743 mm` mercury , calculate the pressure of the gas in bar?
Strategy : The pressure of the gas inside the bulb is greater than the external atmospheric pressure because the height of mercury column in the left arm is less than in the right arm.Therefore ,
`p_("gas") ("in cm") = p_("atom") ("in cm") + h cm`

Explanation

The hight developed due to pressure of gas
` = 43.7 - 15.6 = 28. 1cm`
`:. H .d .g = 28.1 xx 13.6 xx 980 = 374516.8 "dyne"//cm^(2)`
` = (374516.8)/(76 xx 13.6 xx 980) atm = 0.37 atm`
`p_(gas) = P_(atm) + h. d .g`
`:. P_(gas) = (743)/(760) + 0.37 = 1.347 atm`
`(P_(atm) = (743)/(760) atm)`
` = (1.347)/(0.987) =1.36` bar .