`20 dm^(3)` of `SO_(2)` diffuse through a porous partitions in 60 second What volume be `O_(2)` will diffuse under similar conditions in 30 second ? .

Explanation

According to Graham's law of diffusion
`(r_(1))/(r_(2)) = (V_(1))/(t_(1)) xx (t_(2))/(V_(2)) sqrt(((M_(2))/(M_(1))))`
or `(20)/(60) xx (30)/(V) = sqrt(((32)/(64)))`
`V =14 .14 dm^(3)` .