A gas in an open container is heated from `27^(@)C` to `127^(@)C` The fraction of the original amount of gas remaining in the container will be .

Options

A. `3//4`
B. `1//4`
C. `1//2`
D. `1//8`

Explanation

One heating a gas in a open container
(P constt `V` constt) moles of gas go out
Thus `n_(1) T_(1) =n_(2) T_(2)`
or `n_(1) xx 300 =n_(2) xx 400`
`:. N_(2) = (3n_(1))/(4)`
`:.` Fraction of moles of gas left
`=(n_(2))/(n_(1)) = (3n_(2))/(4n_(1)) = (3)/(4)` .