The circulation of blood in human body supplies `O_(2)` and releases `CO_(2)` The concentration of `O_(2)` and `CO_(2)` is variable but on the average `100mL` blood contains `0.02 g` of `O_(2)` and `0.08 g` of `CO_(2)` Calcultate the volume of `O_(2)` and `CO_(2)` at 1 atm and body temperature `37^(@)C` assuming 10 llitre blood in human body .

Options

A. 2 litre 4 litre
B. 1.5 litre 4.5 litre
C. 1.59 litre, 4.62 litre
D. `3.82 litre, 4.62 litre

Explanation

`:. 100 mL` bood has `0.02g O_(2)` and `0.08g CO_(2)`
`:. 10,000 mL` blood has `2g O_(2)` and `8gCO_(2)`
Now `PV =(w)/(m) RT`
For `O_(2): 1 xx V = (2)/(32) xx 0.0821 xx 310`
`V_(O_(2)) = 1.59` litre
For `CO_(2): 1 xx V = (8)/(44) xx 0.0821 xx 310`
`V_(CO_(2)) =4.62 litre` .