Equal moles of `CO,B_(2)H_(6),H_(2)` and `CH_(4)` are placed in a container If a hole was made in container after 5 minute partial pressure of gases in container would be (at.wt of `C,O,B` and `H` are `12,16,1` and 1 respectively) .

Options

A. `P_(CO ) gt P_(B_(2)H_(6)) gt P_(H_(2)) gt P_(CH_(4))`
B. `P_(CO) =P_(B_(2))H_(6) gt P_(CH_(4)) gt P_(H_(2))`
C. `P_(CO) gtP_(B_(2)H_(6)) gt P_(H_(2)) gt P_(CH_(4))`
D. `P_(B_(2))H_(6) gt P_(H_(2)) gt P_(CH_(4)) gt P_(CO)`

Explanation

`CO` and `B_(2)H_(6)` have same molecular mass. The diffusion of lighter gas will be more Thus moles coming out from container will show
`H_(2) gtCH_(4) gtCO =B_(2)H_(6)` .