Volume coefficient according to Charles' law is .

Options

A. Change in volume of gas for each `1^(@)C` rise in temperature
B. `3.661 xx 10^(-3) C^(-1)`
C. `(V-V_(0))/(tV_(0))`
D. Either of these

Explanation

Volume coefficient `alpha` is given as
`V_(0) =K xx 273.15`
`V_(t) = Kxx (t +273.15)`
`:. (V_(t))/(V_(0)) = (t +273.15)/(273.15) =[1+(t)/(273.5)]`
or `V_(t) = V_(0) [1+alpha]`
where `alpha = (1)/(273) = 3.66 xx 10^(-3)` .