Volume coefficient at 273 K according to Charles' law is .

Options

A. Volume of coefficient ` =(V_(t)-V_(0))/(t.V_(0))` where `V_(t)` is volume at `t^(@)C` and `V_(0)` is volume at `0^(@)C` .
B. Volume coeefficient `=3.66 xx 10^(-3)`
C. Volume coefficient `=(1)/(273+t)`
D. Volume coefficient is volume of gas for each `1^(@)C` rise in temperature .

Explanation

According to Charles' law
`V_(0) =K xx 273, V_(t) = K xx (273 +t)`
` :.(V_(t))/(V_(0)) = (273+t)/(273) = (1+(t)/(273))`
`:. V_(t) = V_(0) (1 +alphat)`
The volume coefficient `alpha = (1)/(273)` .