Home
Class 11
CHEMISTRY
XmL of H(2) gas effuses through a hole i...

`XmL` of `H_(2)` gas effuses through a hole in a container is 5 second. The time taken for the effusion of the same volume of the gas specified below under identical conditions is .

A

`10 second : He`

B

`20 second : O_(2)`

C

`25 second : CO`

D

`55 second : CO_(20)`

Text Solution

Verified by Experts

`(X)/(5)xx(t)/(X)=sqrt((32)/(2)) for H_(2)` and `O_(2)`
`t =20 second` .
Promotional Banner

Topper's Solved these Questions

  • GASEOUS STATE

    P BAHADUR|Exercise Exercise B|1 Videos
  • GASEOUS STATE

    P BAHADUR|Exercise Exercise 4|1 Videos
  • GASEOUS STATE

    P BAHADUR|Exercise Exercise 3|1 Videos
  • CHEMICAL EQUILIBRIUM

    P BAHADUR|Exercise Exercise|134 Videos
  • IONIC EQUILIBRIUM

    P BAHADUR|Exercise Exercise|85 Videos

Similar Questions

Explore conceptually related problems

X mL of H_(2) gas effuses through a hole in a container in 5 s . The time taken for the effusion of the same volume of the gas specified below, under identical conditions, is

The constant motion and high velocities of gas particles lead to some important practical consquences. One such consquences is that gases mix rapidly when they come in contact. Take the stopper off a bottle of perfume, for instance, and the odour will spread rapidly through the room as perfume molecules mix with the molecules in the air. This mixing of different gases by random molecular motion and with frequent collision is called diffusion. A similar process in which gas molecules escape without collision through a tiny hole into a vacuum is called effusion. Both the processes follow Graham's law which is mathematically put as r prop sqrt(1//d) . The average distance travelled by molecules between successive collisions is called mean free path. Answer the following questions on the basis of the above information: X mL H_(2) effuses through a hole in a container in 5 s . The time taken for the effusion of the same volume of the gas specified below under identical conditions is

The time taken for effusion of 32 mL of oxygen will be the same as the time taken for effusion under identical condition of :

The time taken for effusion of 64 mL of oxygen will be as the time taken for the effusion of which of the following gases under identical conditions ?

Which of the following gases will have the same rate of effusion under identical conditions ?

P BAHADUR-GASEOUS STATE-Exercise
  1. The compressibility factor for a real gas at high pressure is .

    Text Solution

    |

  2. Arrange the van der Waals constant for the gases .

    Text Solution

    |

  3. XmL of H(2) gas effuses through a hole in a container is 5 second. The...

    Text Solution

    |

  4. The compressibility factor for an ideal gas is .

    Text Solution

    |

  5. According to Graham's law, at a given temperature the ration of rates ...

    Text Solution

    |

  6. A gas will approach ideal behaviour at

    Text Solution

    |

  7. The compressibility of a gas is less than unity at STP .

    Text Solution

    |

  8. The rms velocity of hydrogen is sqrt7 times the rms velocity of nitrog...

    Text Solution

    |

  9. At 100^(@)C and 1 atm, if the density of the liquid water is 1.0 g cm^...

    Text Solution

    |

  10. The root mean square speed of an ideal gas at constant pressure varies...

    Text Solution

    |

  11. Which of the following volume-temperature (V-I) plots represents the b...

    Text Solution

    |

  12. When the temperature is increased surface tension of water .

    Text Solution

    |

  13. Positive deviation from ideal behaviour takes place because of

    Text Solution

    |

  14. The root mean square speed of one mole of a monoatomic gas having mole...

    Text Solution

    |

  15. The ratio of the rate of diffusion of helium and methane under indenti...

    Text Solution

    |

  16. A monoatomic ideal gas undergoes a process in which the ration of P to...

    Text Solution

    |

  17. The given graph represents the variations of compressibility factor Z=...

    Text Solution

    |

  18. The term that is correct for the attractive forces present in a real g...

    Text Solution

    |

  19. For one mole of a van der Waals gas when b =0 and T =30 K the PV vs1//...

    Text Solution

    |

  20. 7g of a gas occupies a volume of 4.1 litre at 300 K If mol wt of gas ...

    Text Solution

    |