4 litre `C_(2)H_(4)` (g) burns in oxygen at `27^(@)C` and 1 atm to produce `CO_(2)` (g) and `H_(2)O` (g) Calculate the volume of `CO_(2)` formed at (a) `27^(@)C` and 1 atm (b) `127^(@) C` and 1atm ( c) `27^(@)C` and 4 atm .

Answer

2

Explanation

`C_(2)H_(4_(g)) + 30_(2_(g))rarr2CO_(2(g)) + 2H_(2)O_(g)`
`:. 1` mole or volume of `C_(2)H_(4)` gives `= 2` volume of `CO_(2)`
`:. 4` volume of `C_(2)H_(4)` gives ` =2 xx 4= 8` litre of `CO_(2)`
Now at `27^(@)C` and `4atm`
`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2)) = (1xx8)/(300) = (4xxV_(2))/(300)`
`V_(2) = 2` litre .