A certain amout of an ideal gas occupies a volume of `1.0m^(3)` at a given temperature and pressure What would be its volume after reducing its pressure to half the initial value and raising the temperature twice the initial value ? .

Answer

4

Explanation

Given, `P_(2) = (1)/(2) P_(1)` and `T_(2) =2T_(1),V_(1) = 1.0m^(3)`
Now `(P_(1)xx1.0)/(T_(1)) = (1xxP_(1)xxV_(2))/(2xx2xxT_(1))`
`V^(2) = 4m^(3)` .