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Calculate the volume occupied by 96 g CH...

Calculate the volume occupied by `96 g CH_(4)` at 16 atm and `27^(@)C(R -0.08` litre atm `K^(-1) mol^(-1))` .

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The correct Answer is:
9
Given `P =16atm, m =16`
`T = 27 +273 = 300K, V =? `
`:. PV = (w)/(m)RT`
`:. V = (wRT)/(Pm) = (96 xx 0.08 xx 300)/(16 xx 16) =9 litre` .
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