An `L.P.G` cylinder contains `15kg` of butane gas at `27^(@)C` and 10 atm pressure It was leaking and its pressure fell down to 8 atm pressure after one day Calculate the amount of leaked gas .

Answer

3

Explanation

Volume of cylinder is constant
`:. P_(1)V =n_(1)RT` and `P_(2)V =n_(2)RT`
or `(P_(1))/(P_(2)) = (n_(1))/(n_(2)) = (w_(1//m))/(w_(2)//m) = (w_(1))/(w_(2)`
`(10)/(8) = (15)/(w_(2))`
or `w_(2) = 12kg`
`:.` Gas leaked ` =15 -12 3kg` .