A cylindrical container with moveable piston initially hold 3.0 mole of a gas at 8.0 atm pressure and a volume of 5.0 litre If piston is moved to create a volume 10.0 litre while simultaneously with drawing 1.5 mole of gas Calculate the final pressure .

Answer

2

Explanation

`PV =nRT` or `(PV)/(n) =RT`
`P_(1) =8atm, V_(1) =5.0` litre `n_(1) =3.0` mole `P_(2) =?`
`V_(2) =10` litre `n_(2) =1.5` mole
Now `(P_(1)V_(1))/(n_(1)) =(P_(2)V_(2))/(n_(2))`
`(8xx5)/(3)=(P_(2)xx10)/(1.5)`
`P_(2) =2atm` .