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Considering the van der Waals equation o...

Considering the van der Waals equation of state `(P+a//V^(2))(V-b) =RT` for ammonia `(NH_(3))` and nitrogne `(N_(2))` the value of a for `NH_(3)` is larger than that of `N_(2)`
Ammonia has a lower molecular weight than nitrogen .

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The value of 'a' for NH_(3) is greater than that of N_(2) . This means:

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Statement-1. Considering van der Waals' equation of state of NH_(3) and N_(2) [P+(a)/(V^(2))][V-b] = RT The value of van der Waals' constant for NH_(3) is more than tht for N_(2) Statement-2. Ammonia has lower molecular mass than N_(2) .

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P BAHADUR-GASEOUS STATE-Exercise
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