Home
Class 11
CHEMISTRY
Considering van der Waals equation of st...

Considering van der Waals equation of state for a real gas `(P+n^(2)a//V^(2))(V-nb) =nRT` the constant 'a' for `O_(2)` is less than that for `H_(2)O_(g)`
The molar mass of `O_(2)` is almost twice that of `H_(2)O` .

Text Solution

Verified by Experts

Explantion is correct reason for statement
Promotional Banner

Topper's Solved these Questions

  • GASEOUS STATE

    P BAHADUR|Exercise Exercise B|1 Videos

  • GASEOUS STATE

    P BAHADUR|Exercise Exercise 4|1 Videos

  • GASEOUS STATE

    P BAHADUR|Exercise Exercise 3|1 Videos

  • CHEMICAL EQUILIBRIUM

    P BAHADUR|Exercise Exercise|134 Videos

  • IONIC EQUILIBRIUM

    P BAHADUR|Exercise Exercise|85 Videos

Similar Questions

Explore conceptually related problems

The van der Waal equation of gas is (P + (n^(2)a)/(V^(2))) (V - nb) = nRT

The unit of the van der Waals gas equation parameter 'a' in (P+(an^(2))/(V^(2)))(V-nb)=nRT is :

In the van der Waals equation (P + (n^(2)a)/(V^(2)))(V - nb) = nRT the constant a reflects the actual volume of the gas molecules.

Units of a and b in van der Waal's equation (P+(an^(2))/(V^(2)))(V-nb)=nRT are

Statement-1. Considering van der Waals' equation of state of NH_(3) and N_(2) [P+(a)/(V^(2))][V-b] = RT The value of van der Waals' constant for NH_(3) is more than tht for N_(2) Statement-2. Ammonia has lower molecular mass than N_(2) .

In the Van der Waals equation (P + (n^(2)a)/(V^(2))) (V-nb) = nRT , why is the term n^(2)a//V^(2) positive in sign.

Using van der Waals equation (P+(a)/(V^(2)))(V-b)=RT , answer the following questions: The van der Waals equation explains the behaviour of

The van der Waals, equation for n moles of real gas is: (P+(n^(2)a)/(V^(2)))(V - nb) = nRT where P is the pressure, V is the volume , T is the absolute temperature, R is the molar gas constant and a, b are van der Waal's constant. Which of the following have the same dimension as those of PV ?

The volume strength of 1 M H_(2)O_(2) is : (Molar mass of H_(2)O_(2) = 34 g mol^(-1)

P BAHADUR-GASEOUS STATE-Exercise
  1. The heat capacities of the diatomic molecules attain a limiting value ...

    Text Solution

    |

  2. The freezing point of 0.05M urea solution is differnet from that of 0....

    Text Solution

    |

  3. Considering van der Waals equation of state for a real gas (P+n^(2)a//...

    Text Solution

    |

  4. When iodine is heated under atmospheric pressure conditions it transfo...

    Text Solution

    |

  5. The viscosity of an ideal gas is independent of pressure at constant t...

    Text Solution

    |

  6. What per cent of its temperature pressure and volume are to 110^(@)C, ...

    Text Solution

    |

  7. A quantity of gas is collected in a gradutated tube over the mercury. ...

    Text Solution

    |

  8. Air is pumped into the tubes of cycle rickshaw at a pressure of 2 atm....

    Text Solution

    |

  9. An iron meteorite was analysed for its argon content The amount of Ar ...

    Text Solution

    |

  10. shows two vessels A and B with rigid walls containing ideal gas. The p...

    Text Solution

    |

  11. An evacuated bulb of unknown volume is filled with a sample of H(2) ga...

    Text Solution

    |

  12. Two flasks of equal volume connected by a narrow tube (of negligible v...

    Text Solution

    |

  13. An open flask contains air at 27^(@)C Calculate the temperature at whi...

    Text Solution

    |

  14. A bulb of three litre capacity filled with air is heated from 27^(@)C ...

    Text Solution

    |

  15. The density of helium is 0.1784 kg//m^(3) at STP. If a given mass of h...

    Text Solution

    |

  16. A spherical ballon of 21 cm diameter is to be filled with hydrogen at ...

    Text Solution

    |

  17. A2 litre vessel is filled with air at 50^(@)C and pressure of 3 atm. T...

    Text Solution

    |

  18. In a basal metabolism measurements timed at 6.0 minute a patient exhal...

    Text Solution

    |

  19. A gas cylinder contains 370 g oxygen at 30.0 atm pressure and 25^(@)C....

    Text Solution

    |

  20. Calculate the change in pressure when 1.04 mole of NO and 20.0gO(2) in...

    Text Solution

    |