When `SO_(2)` is passed through an acidified `K_(2)Kr_(2)O_(7)` solution, the oxidation state of sulphur changes from

Options

A. `+4` to `0`
B. `+4` to `+2`
C. `+4` to `+6`
D. `+6` to `+4`

Answer

C

Explanation

`6e+(Cr^(6+))_(2)rarr2Cr^(3+)`
`S^(4+)rarrS^(6+)rarr2e`