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Tailing of mercury can be removed by:...

Tailing of mercury can be removed by:

A

`H_(2)O_(2)`

B

`O_(3)`

C

`O_(2)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
The `Hg_(2)O` formed during oxidation of `Hg` by `O_(3)`, i.e., tailing of `Hg` is reduced back by `H_(2)O_(2)`.
`Hg_(2)O+H_(2)O_(2)rarrHg_(2)+H_(2)O+O_(2)`
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P BAHADUR-REDOX REACTIONS-Exercise 3(A) Objective problems
  1. Hydrogen gas will not reduce:

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  2. The oxidation state of Cr in CrO(5) is:

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  3. Tailing of mercury can be removed by:

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  4. The oxidation number and covalency of sulphur in the sulphur molecule ...

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  5. How many mole of electrons are involved in the reduction of one mole o...

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  6. For the redox reaction MnO(4)^(ө)+C(2)O(4)^(2-)+H^(o+)rarrMn^(2+)+CO...

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  7. It is found that V forms a double salt isomorphous with Mohr's salt. T...

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  8. The oxidation number of sulphur in H(2)S(2)O(8) is:

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  9. One mole of N(2)H(4) loses ten moles of electrons to form a new compou...

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  10. Number of electron involved in the reduction of Cr(2)O(7)^(2-) ion in ...

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  11. Oxidation state of nitrogen is incorrectly given for:

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  12. The number of electrons lost in the following change is Fe+H(2)Orarr...

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  13. The oxidation number of C in HNC is

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  14. Oxidation number of Cl in NOClO(4) is:

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  15. Oxidation number of S in [(CH(3))(2)SO] is:

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  16. The equivalent weight of salt KHC(2)O(4).H(2)C(2)O(4).4H(2)O when us...

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  17. The oxidation number of Cl in CaOCl(2) is

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  18. Oxidation number of carbon in carbon sub-oxide is:

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  19. The colour of K(2)Cr(2)O(7) changes from red-orange to lemon-yellow on...

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  20. 50 mL of 0.1M solution of a salt reacted with 25 mL of 0.1M solution o...

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