The oxidation number and covalency of sulphur in the sulphur molecule `(S_(8))` are respectively:

Options

A. `0` and `2`
B. `+6` and `8`
C. `0` and `8`
D. `+6` and `2`

Explanation

To solve the question regarding the oxidation number and covalency of sulfur in the sulfur molecule \( S_8 \), we can follow these steps:

### Step 1: Determine the Oxidation Number
1. **Understand the Elemental State**: In chemistry, the oxidation number of an element in its elemental form is always zero.
2. **Identify the Element**: In this case, we are dealing with sulfur in the form of \( S_8 \), which is its most stable and common allotrope.
3. **Conclusion**: Therefore, the oxidation number of sulfur in \( S_8 \) is 0.

### Step 2: Determine the Covalency
1. **Define Covalency**: Covalency refers to the number of bonds an atom can form with other atoms. It indicates how many other atoms are bonded to a particular atom.
2. **Analyze the Structure of \( S_8 \)**: The \( S_8 \) molecule has a crown-like structure where each sulfur atom is bonded to two other sulfur atoms.
3. **Count the Bonds**: Each sulfur atom in \( S_8 \) forms two bonds with its neighboring sulfur atoms.
4. **Conclusion**: Hence, the covalency of sulfur in \( S_8 \) is 2.

### Final Answer
- The oxidation number of sulfur in \( S_8 \) is **0**.
- The covalency of sulfur in \( S_8 \) is **2**.

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