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Number of electron involved in the reduc...

Number of electron involved in the reduction of `Cr_(2)O_(7)^(2-)` ion in acidic solution to `Cr^(3+)` is:

A

`3`

B

`4`

C

`2`

D

`6`

Text Solution

Verified by Experts

The correct Answer is:
D
`(Cr^(6+))_(2)+6erarr2Cr^(3+)`
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P BAHADUR-REDOX REACTIONS-Exercise 3(A) Objective problems
  1. The oxidation number of sulphur in H(2)S(2)O(8) is:

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  2. One mole of N(2)H(4) loses ten moles of electrons to form a new compou...

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  3. Number of electron involved in the reduction of Cr(2)O(7)^(2-) ion in ...

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  4. Oxidation state of nitrogen is incorrectly given for:

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  5. The number of electrons lost in the following change is Fe+H(2)Orarr...

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  6. The oxidation number of C in HNC is

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  7. Oxidation number of Cl in NOClO(4) is:

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  8. Oxidation number of S in [(CH(3))(2)SO] is:

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  9. The equivalent weight of salt KHC(2)O(4).H(2)C(2)O(4).4H(2)O when us...

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  10. The oxidation number of Cl in CaOCl(2) is

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  11. Oxidation number of carbon in carbon sub-oxide is:

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  12. The colour of K(2)Cr(2)O(7) changes from red-orange to lemon-yellow on...

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  13. 50 mL of 0.1M solution of a salt reacted with 25 mL of 0.1M solution o...

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  14. In a reaction, 4 mole of electrons are transferred to 1 mole of HNO(3)...

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  15. During developing of an exposed camera, film one step involves in the ...

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  16. The ratio of equivalent weights of C(2)H(5)OH in the following reactio...

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  17. An element A in a compound ABD has oxidation number A^(n-). It is oxi...

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  18. N(2) + 3 H(2) rarr 2NH(3) Molecular weight of NH(3) and N(2) are x(1...

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  19. Equivalent weight of FeC(2)O(4) during its reaction with KMnO(4) is:

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  20. The no.of electrons involved in the change, Fe(3)O(4)rarrFe(2)O(3):

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