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The no.of electrons involved in the chan...

The no.of electrons involved in the change,
`Fe_(3)O_(4)rarrFe_(2)O_(3)`:

A

`2`

B

`8`

C

`6`

D

`4`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the number of electrons involved in the change from \( \text{Fe}_3\text{O}_4 \) to \( \text{Fe}_2\text{O}_3 \), we will follow these steps: ### Step 1: Determine the oxidation states of iron in both compounds. - In \( \text{Fe}_3\text{O}_4 \): - Oxygen has an oxidation state of -2. - Let the oxidation state of iron be \( x \). - The equation for the oxidation states is: \[ 3x + 4(-2) = 0 \implies 3x - 8 = 0 \implies 3x = 8 \implies x = \frac{8}{3} \approx +2.67 \] - In \( \text{Fe}_2\text{O}_3 \): - Again, let the oxidation state of iron be \( y \). - The equation for the oxidation states is: \[ 2y + 3(-2) = 0 \implies 2y - 6 = 0 \implies 2y = 6 \implies y = 3 \] ### Step 2: Calculate the change in oxidation states. - The oxidation state of iron in \( \text{Fe}_3\text{O}_4 \) is \( +\frac{8}{3} \) and in \( \text{Fe}_2\text{O}_3 \) is \( +3 \). - The change in oxidation state for one iron atom can be calculated as follows: \[ \text{Change} = \left( +\frac{8}{3} - 3 \right) = \left( +\frac{8}{3} - \frac{9}{3} \right) = -\frac{1}{3} \] ### Step 3: Determine the total change for all iron atoms. - In \( \text{Fe}_3\text{O}_4 \), there are 3 iron atoms: \[ \text{Total change} = 3 \times \left(-\frac{1}{3}\right) = -1 \] ### Step 4: Relate the change in oxidation state to the number of electrons transferred. - A decrease in oxidation state indicates a gain of electrons (reduction). - Since the total change is -1, it means that 1 electron is gained in the process. ### Conclusion: The number of electrons involved in the change from \( \text{Fe}_3\text{O}_4 \) to \( \text{Fe}_2\text{O}_3 \) is **1 electron**.

To determine the number of electrons involved in the change from \( \text{Fe}_3\text{O}_4 \) to \( \text{Fe}_2\text{O}_3 \), we will follow these steps: ### Step 1: Determine the oxidation states of iron in both compounds. - In \( \text{Fe}_3\text{O}_4 \): - Oxygen has an oxidation state of -2. - Let the oxidation state of iron be \( x \). - The equation for the oxidation states is: \[ ...
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The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. Equivalent weight of Fe_(2)O_(3) in terms of its mol. weight in the change Fe_(3)O_(4)rarrFe_(2)O_(3) is

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P BAHADUR-REDOX REACTIONS-Exercise 3(A) Objective problems
  1. N(2) + 3 H(2) rarr 2NH(3) Molecular weight of NH(3) and N(2) are x(1...

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  2. Equivalent weight of FeC(2)O(4) during its reaction with KMnO(4) is:

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  3. The no.of electrons involved in the change, Fe(3)O(4)rarrFe(2)O(3):

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  4. How many gram of I(2) are present in a solution which requires 40 mL o...

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  5. What weight of FeSO(4) ( mol.wt. =152) will be oxidised by 200 mL of n...

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  6. 25 mL of 0.50M H(2)O(2) solution is added to 50 mL of 0.20 M KMnO(4) i...

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  7. What volume of O(2) measured at standard condition will be formed by t...

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  8. The number of Fe^(2+) ion oxidised by one mole of MnO(4)^(-) ions is:

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  9. What mass of HNO(3) is needed to convert 5g of the iodine into iodic a...

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  10. Number of K^(+) ions present in one litre of M//5KMnO(4) solution are:

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  11. When the ion Cr(2)O(7)^(2-) acts as an oxidant in acidic aqueous solut...

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  12. What volume of 3 molar HNO(3) is needed to oxidise 8 g of Fe^(3+), HNO...

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  13. Given that 50 0 mL of 0.01M Na(2)S(2)O(3) solution and 5xx10^(-4) mole...

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  14. Given that 50 0 mL of 0.01M Na(2)S(2)O(3) solution and 5xx10^(-4) mole...

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  15. Given that 50 0 mL of 0.01M Na(2)S(2)O(3) solution and 5xx10^(-4) mole...

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  16. Given that 50 0 mL of 0.01M Na(2)S(2)O(3) solution and 5xx10^(-4) mole...

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  17. 4I^(-)+Hg^(2+)rarrHgI(4)^(2-) , 1 mole each of Hg^(2+) and I^(-) will ...

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  18. 1 mole of ferric oxalate is oxidised by x mole of MnO(4)^(-) in acidic...

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  19. 0.3 g of an oxalate salts was dissolved in 100 mL solution. The soluti...

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