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0.3 g of an oxalate salts was dissolved ...

`0.3 g` of an oxalate salts was dissolved in `100 mL` solution. The solution required `90 mL` of `N//20 KMnO_(4)` for complete oxidation. The `%` of oxalate ion in salt is:

A

`33%`

B

`66%`

C

`70%`

D

`40%`

Text Solution

Verified by Experts

The correct Answer is:
B
`"Meq. of oxalate" = "Meq. Of" KMnO_(4)`
`(w)/(88/2) xx 1000 = 90 xx (1)/(20)`
`:. w_("oxalate") = 0.198 g`
`% "oxalate " = (0.198)/(0.3) xx 100 = 66%`
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