`3` mole of `FeSO_(4)` are oxidised by `a` mole of `KMnO_(4)` in acidic medium whereas `3` moles of `FeC_(2)O_(4)` are oxidised by `b` mole of `KMnO_(4)` in acidic medium, the ratio of `a` and `b` is:

Options

A. `1//3`
B. `1//2`
C. `1//4`
D. `1//5`

Answer

A

Explanation

`{:(,Fe^(2+),rarr,Fe^(3+)+,e),(5e+,Mn^(7+),rarr,Mn^(2+),):}`
or `5 "mole" Fe^(2+)-=1"mole" KMnO_(4)`
`:. 3"mole" Fe^(2+)-=(3)/(5)"mole" KMnO_(4)=a`
`{:(Fe^(2+)rarrFe^(3+)+e),((C^(3+))_(2)rarr2C^(4+)+2e),(bar(FeC_(2)O_(4)rarrFe^(3+)+2C^(4+)+3e)),( :. 5 "mole"FeC_(2)O_(4)=3"mole"KMnO_(4)),( :. 3 "mole" FeC_(2)O_(4)=(9)/(5)"mole"KMnO_(4)=b):}`