A satellite which is geostationary in a particular orbit is taken to another orbit. Its distance from the centre of earth in new orbit is 2 times that of the earlier orbit. The time period in the second orbit is

Options

A. 4.8 hours
B. `48sqrt(2)` hours
C. 24 hours
D. `24sqrt(2)`hours

Answer

B

Explanation

As per formula ` T=(2pi)/(R ) sqrt(((R+h)^(3))/(g))`
Time period of 1st geostationary satellite `=R+h`
` therefore (24)/(T) = sqrt((R+h)^(3))/({2(R+h)}^(3))=sqrt((1)/(8))`
`implies T=24 sqrt(8)=48 sqrt(2)`hours