A capacitor of capacitance `5muF` is connected to a source of constant emf of 200V for a long time then the swict was shifited to contact 2 form contant 1. The total amount fo heat generated in the ` 500 omega` resistance thereafter .

Options

A. `1//32 J`
B. `3//32J`
C. `2//32J`
D. `5//32J`

Answer

C

Explanation

Energy stored in capacitor
` = (1)/(2) CV^(2) = (1)/(2) xx 5 xx 10^(-6) xx (200)^(2) = 10 ^(-1)J`
The fraction lost in ` 500 Omega` is 5/8 of total so `H = (5)/(8) xx (1)/(10) = (1)/(16) J = (2)/(32)J`