The fossil bone has a `.^(14)C` : `.^(12)C` ratio, which is `[(1)/(16)]` of that in a living animal bone. If the half -life of `.^(14)C` is `5730` years, then the age of the fossil bone is :

Options

A. 11460 years
B. 17190 years
C. 22920 years
D. 45840 years

Answer

C

Explanation

Here `(N)/(N_(0))=1/16 =(1)/(2 ^(t)//T_(h))("Here "T_(h)to ` half life)
`implies (1)/(2^(4)) =(1)/(2 ^(t//5730))`
`implies t =5730xx4=22920` years