A 60 kg body moving with speed 12 m/s collides inelastically with another body of mass 50 kg moving in same direction with speed 2 m/s. After collision the 50 kg body moves with a speed of 10 m/s. The value of coefficient of restitution (e) is :-

Options

A. `7/15`
B. `7/10`
C. `9/16`
D. `15/19`

Answer

A

Explanation

`m_(1) u_(1) +m_(2) u_(2) =m_(1) v_(1) +m_(2) v_+(2)`
`(60)12+(50)2=(60) v_(1) +(50) 10`
`v_(1) =(16)/(3) m//s `
`e =-(v_(2)-v_(2))/(u_(1)-u_(2))`
`=(10-(16)/(3))/(12-2)=7/15`