Home
Class 12
CHEMISTRY
The resistance of 0.5M solution of an el...

The resistance of `0.5M` solution of an electrolyte in a cell was found to be `50 Omega`. If the electrodes in the cell are `2.2 cm` apart and have an area of `4.4 cm^(2)` then the molar conductivity (in `S m^(2) mol^(-1))` of the solution is

A

0.2

B

0.02

C

0.002

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`K = (1)/(R )((1)/(A))`
`k = (1)/(50) ((2.2)/(4.4))`
` k = 0.01 Omega^(-1) cm^(-1) = 1Omega^(-1) m^(-1)`
`VV_(m) = (K)/(M xx 10^(3)) = (1)/(0.5xx 10^(3))`
`VV_(m) = 0.002 s m^(2) mol^(-1)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The resistance of 0.5 N solution of an electroolyte in a conductivity cell was found to be 45 ohms. If the electrodes in the cell are 2.2 cm apart and have an area of 3.8cm^(2) then the equivalent conductance (in Scm^(2)eq^(-1) ) of a solution is

The resistance of a (N)/(10)KCl aqueous solution is 2450Omega . If the electrodes in the cell are 4cm apart abd area having 7 cm^(2) each, the molar conductance of the solution will be

The resistance of 0.5 M solution of and electrolyte enclosed enclosed between two platinuim electrodes 1.56 cm apart and having an are of 2.0cm^(3) was found to be 30 cm. Calculate the molar conductivity of the electrolyte/.

The resistance of aN//10KCI solution is 245 Omega . Calculate the equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each haveing an area of 7.0 sq.cm .

(a). The resistance of a decinormal solution of an electrolyte in a conductivity cell was found to be 245 ohms. Calculate the equilvalet conductivity of the solution if the electrodes in the cell were 2 cm apart and each has an area of 3.5 sq. cm. (b). The conductivity of 0.001028M acetic acid is 4.95xx10^(-5)Scm^(-1) . Calculate its dissociation constant if ^^_(m)^(@) for acetic acid is 390.5Scm^(2_mol^(-1)

The resistance of an N//10 KCl solution is 245 ohms . Calculate the equivalent conducatnce of the solution id the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq.cm.