17.4% (wt.//vol.) K(2)(SO(4)) solution a...

`17.4%` (wt.`//`vol.) `K_(2)(SO_(4))` solution at `27^(@)C` isotonic to `5.85%` (wt.`//`vol.) `NaCl` solution at `27^(@)C`. IF `NaCl` is `100%` ionised, what is `%` ionisation of `K_(2)SO_(4)` in aq. solution?

A

`25%`

B

`75%`

C

` 50%`

D

None of this

Verified by Experts

The correct Answer is:

C

`pi _1 =pi_2`
` i_1C_1 =i_2 c_2`
` i_1 xx (17.4)/( 174) =2xx (5.85)/(58.5)`
`i_1=2`
`1+(3-1)alpha =2`
` alpha =(1)/(2) =50%`

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