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A force applied on a particle of mass 2 ...

A force applied on a particle of mass 2 kg changes its velocity from `(hati + 2 hatj ) ms^(-1) "to" (4hati +6hatj )ms^(-1)`​. The work done by the force in this process is :-

A

45J

B

46J

C

47J

D

48J

Text Solution

Verified by Experts

The correct Answer is:
C
`K=(1)/(2)(2)[(sqrt(4^(2)+6^(2)))^(2)-(sqrt(1^(2)+2^(2)))^(2)]`
`=(16+36-5)=47 J`
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