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A torque of 30 N-m is acting on a wheel ...

A torque of 30 N-m is acting on a wheel of mass 5 kg and moment of inertia `2 kg-m​^(2)`​. If wheel starts rotating from rest then its angular displacement in 10 seconds will be-

A

750rad

B

1500rad

C

300rad

D

6000rad

Text Solution

Verified by Experts

The correct Answer is:
A
`tau = I , alpha =(tau)/(I)=(30)/(2) = 15 rad //s^(2)`
`theta =(1)/(2) alpha t^(2) =(1)/(2) xx15xx(10)^(2) =750 rad `
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