A disc of mass M and radius R is rolling with angular speed `omega` on a horizontal plane as shown in figure. The magnitude of angular momentum of the disc about the origin O is

Options

A. `(1//2)Mg^(2) omega `
B. `MR^(2) omega`
C. `(3//2) MR^(2)omega`
D. `2MR^(2)Omega`

Answer

C

Explanation

`L=MVR + I omega `
here `V=Omega R, I= (MR^(2))/(2) `
`L=M(Romega ) R +(MR^(2))/(2) omega =(3)/(2) MR^(2)omega `