If the equation of transverse wave is `Y=2 sin (kx-2t),` then the maximum particle velocity is

The equation of a transverse wave is y=asin2pi[t-(x//5)] , then the ratio of maximum particle velocity and wave velocity is

The equation of progressive wave is y = A sin (kx - omega t) . What is the maximum velocity?

The equation of a travelling wave is, Y = A sin 2pi (pt-x//5) Then the ratio of maximum particle velocity to wave velocity is,

The equation of a travelling wave is, Y = A sin 2pi (pt-x//5) Then the ratio of maximum particle velocity to wave velocity is,

A travelling wave in a stretched string is described by the equation y = A sin (kx - omegat) the maximum particle velocity is

A travelling wave in a stretched string is described by the equation y = A sin (kx - omegat) the maximum particle velocity is

A transverse wave is described by the equation y= A sin 2 pi (vt - x/lambda) . The maximum particle velocity is equal to four times the wave velocity if

A transverse wave is described by the equation Y=Y_(0) sin 2 pi (ft-frac(x)(lambda) . The maximum particle velocity is four times the wave velocity if