If `bar a+2 bar b+3 bar c=bar 0` then `bar a xx bar b +bar b xx bar c+bar c xx bar a=`

if bar a+2 bar b+3bar c=bar 0 then bar axxbar b+bar b xx bar c+bar cxx bara = lambda (bar b xx bar c) ,where lambda=

Prove that [[bar a xx bar p, bar b xx bar p, bar cxx bar r]]+[[bar axx bar q, bar b xx bar r, bar c xx bar p]]+[[bar a xx bar r, bar b xx bar p,bar c xx bar q]]=0

If bar a = 2 bar I + bar j - bar k, bar b = - bari + 2 bar j - 4 bar k and bar c = bar I + bar j + bar k , then find ( bar a xx bar b) cdot (bar b xx bar c) .

If bar r=l(bar b xx bar c)+m(bar c xx bar a)+n(bar a xx bar b) and [bar a bar b bar c]=2 , then l+m+n is equal to

If 4bar(a)+5bar(b)+9bar( c )=0 then (bar(a)xx bar(b))xx[(bar(b)xx bar( c ))xx(bar( c )xx bar(a))] = ………..

If bar(a)+bar(b)+bar( c )=0 , then show that bar(a)xx bar(b)=bar(b)xx bar( c )=bar( c )xx bar(a) . Interpret the result geometrically.

bar a, bar b, bar c are three vectros, then prove that: (bar a xx bar b) xx bar c = (bar a. bar c) bar b-(bar b. bar c) bar a.

If bar(a).bar(b) = bar(a).bar(c ) and bar(a) xx bar(b) = bar(a) xx bar(c ), bar(a) != 0 , then show that bar(b) = bar(c ) .

If 4bar(a)+5bar(b)+9bar(c)=bar(0) then (bar(a)xxbar(b))xx[(bar(b)xxbar(c))xx(bar(c)xxbar(a))]=