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Find the value p for which the points (-...

Find the value p for which the points (-1,-1) (2, p) and (8,11) are collinear

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area of `/_\ ABC = 0`
area of triangle = `1/2|(x_1,y_1,1),(x_2,y_2,1),(x_3,y_3,1)| = 0`
`1/2|(-1,-1,1),(2,p,1),(8,11,1)|=0`
`-p+22-8-[8p-11-2] = 0`
`-p + 22 - 8 - 8p + 13=0`
`27 - 9p= 0`
`27= 9p`
`p = 27/9 = 3`
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