ज्ञात करें `int(dx)/(1+cos x)`

Explanation

`int(dx)/(1+cos x)=int(dx)/(2cos^2x//2)`
`=1/2intsec^2""x/2dx=1/2(tanx//2)/(1/2)+c=tan""x/2+c`
`int(dx)/(1+"cos x")=int(1-cosx)/((1+cos x)(1-cosx))dx`
`=int("cosec"^2x-"cosecx cot x")dx=int"cosec"^2" x dx "-int " cosecx cot x dx"`
`=cot x -(-"cosec x")+c=cotx + "cosec x + c"` .