ज्ञात करें `int(cos2x-cos2alpha)/(cosx-cosalpha)dx`

Explanation

`int(cos2x-cos2alpha)/(cosx-cosalpha)dx=int([2cos^2x-1-(2cos^2alpha-1)])/(cos x - cos alpha)dx`
`int(2(cos^2x-cos^2alpha))/(cos x - cos alpha)dx=2int(cosx+cos alpha)dx`
`2intcosxdx+2cosalpha int dx`
`=2sinx + 2 cos alpha* x + c =2sin x +2x cos alpha+c`