ज्ञात करें `int(sinx)/(1+sin x)dx`

Explanation

`int(sinx)/(1+sin x)dx=int(1+sinx-1)/(1+sinx)dx=intdx-int(dx)/(1+sinx)`
`=x-int(1-sinx)/(1-sin^2x)dx=x-int(1-sinx)/(cos^2x)dx`
`=x-int sec^2" x dx "+int"tan x sec x dx = x - tan x + sec x + c"`