ज्ञात करें `int x(1-x)^23dx`

Explanation

`z=1-x,` रखे तो `dz=-dx`
अब, `1=-int(1-z)z^(23)dz=-[z^(24)/24-z^(25)/25]+c`
`=-[((1-x)^24)/24-((1-x)^25)/25]+c`
`=-((1-x)^24)/600[25-24(1-x)]+c=-((1-x)^24(1+24x))/600+c`