ज्ञात करें `int (dx)/(sqrt(1+cos 2x))`

Explanation

`int(dx)/(sqrt(1+cos2x))=int (dx)/(2cos^2x)=1/sqrt2int(dx)/(cosx)`
`=1/sqrt2intsec x dx=1/sqrt2" log|sec x + tan x|+c" "[becauseintsec x dx = log | sec x + tan |]`