ज्ञात करें `int(sin(x-alpha))/(sin(x+alpha))dx`

Explanation

`int(sin(x-alpha))/(sin(x+alpha))dx=int(sin(bar(x+a)-2alpha))/(sin(x+alpha))dx`
`=int(sin(x+alpha)cos 2 alpha-cos(x-alpha)sin2alpha)/(sin(x+alpha))dx`
`=cos 2alphaintdx-sin 2 alphaintcot ( x+alpha)dx`
`=x cos 2alpha-sin2alphalog| sin (x+alpha)|+c`