ज्ञात करें `int ((sin^(-1)x)^3)/sqrt(1-x^2) dx`

Explanation

माना की `x=sin theta`, तो ` dx = cos theta d theta`
अब, `int ((sin^(-1)x)^3)/sqrt(1-sin^2) dx =int theta^3/sqrt(1-sin^2 theta)cos theta d theta = int theta^3d theta`
`=theta^4/4+c=((sin^(-1)x)^4)/4+c`