ज्ञात करें `int ( 1+x) log x dx`

Explanation

माना की `I =((1+x)^2)/2"log x -"int ((1+x)^2)/2*1/2"" dx`
`=1/2 (1+x)^2" log x "-1/2 int ( 1+ 2x +x^2)/x""dx`
`=1/2 (1+x)^2 logx -1/2 int (1/x +2 +x) dx`
`=1/2 (1+x)^2"log x "-1/2(log x + 2x + x^2/2)+c`
`=(x+x^2/2)"log x -" (x-x^2/4)+c`