ज्ञात करें `int sin^(-1) sqrtx dx`

Explanation

`I = int 1sin^(-1)dx`
`=x sin^(-1)sqrtx-int1/sqrt(1-x)1/(2sqrtx)"x dx = x sin"^(-1)sqrt(x)-1/2 intsqrt(x/(1-x))dx`
`=x sin^(-1) sqrtx -1/2 [sin^(-1)sqrtx -sqrtxsqrt(1-x)]+c`
`int sqrt(x/(1-x)dx)` , ज्ञात करने के लिए `x = sin^2 theta` रखें |