ज्ञात करें `int (x-1)/((x+1)^3)e^x dx`

Explanation

`I = int (x-1)/((x+1)^3)e^x dx = int (x+1-2)/((x+1)^3)dx`
`=inte^x[1/((x+1)^2)+(-2)/((x+1)^3)]dx`
`=int e^x [ f(x) + f(x)] dx,` जहां `f(x)=1/((x+1)^2)`
`=int e^x [f(x) +f'(x)]dx, `जहां `f(x)1/((x+1)^2)`
`=e^x f(x) +c=e^x/((x+1)^2)+c`