ज्ञात करें `int e^x ((x+2)/(x+4))^2 dx`

Explanation

`I = int e^x (( x+4-2)/(x+4))^2dx =int e^x ( 1-2/(x+4))^2 dx `
` = int e^x[(1-4/(x+4))+4/((x+4)^2))]dx`
`int e^x f(x)+f'(x)]dx` जहां `f(x)=1-4/(x+4)`
`=e^x [f(x)+c=e^x(1-4/(x+4))+c=(xe^(x))/(x+4)+c`