ज्ञात करें `int (dx)/(5+4 cos x )`

Explanation

`I =int (dx)/(5+4((1-tan^2""x/2)/(1+tan^2""x/2)))=int (sec^2""x/2)/(9+tan^(2)""x/2)`
माना की `z= tan""x/2,` तो `dz = 1/2 sec^2 "" x/2 dx`
अब, `I =int (2xz)/(3^2 +z^2) =2 ""1/3 tan^(-1)z/3 +c =1/3""tan^(-1) ( ( tan""x/2)/(3))+c`