रेखा ` vecr = ( hati + 2 hatj - hatk ) + lamda ( hati - hatj + hatk ) ` तथा तल ` vecr * ( 2 hati - hatj + hatk ) = 4 ` के बीच का कोण ज्ञात करे |

Explanation

यदि अभीष्ट कोण ` theta ` है , तो
` cos ( 90^@ - theta ) = ( ( hati - hatj + hatk ) * ( 2 hati - hatj + hatk ) ) / ( sqrt ( 1^ 2 ( - 1 ) ^ 2 + 1 ^ 2 ) sqrt ( 2^ 2 + ( - 1 ) ^ 2 + 1 ^ 2 ) ) = ( 4 ) / ( sqrt 3 sqrt 6 ) `
या ` sin theta = ( 4 sqrt 2 ) / ( 6 ) = ( 2 sqrt 2 ) /( 3 ) `
` therefore theta = sin ^ ( - 1 ) ( ( 2 sqrt2 ) / ( 3 )) `