If `alpha` and `beta` are solutions of `sin^2 x + a sin x+b=0` as well as that of `cos^2x + c cosx + d =0` then `sin(alpha + beta) ` is equal to

If alpha and beta are solutions of sin^(2)x+a sin x+b=0 as well as that of cos^(2)x+c cos x+d=0 then sin(alpha+beta) is equal to

If alpha and beta are solutions of sin^2x+asinx+b=0 as well as of cos^2x+c cosx+d=0 then sin(alpha+beta) is equal to

IF cos ( alpha + beta ) =0 then sin ( alpha + 2 beta ) is equal to

If alpha, beta are solutions of a cos x + b sin x = c then cos alpha + cos beta=

If alpha, beta are solutions of a cos x + b sin x = c then sin alpha + sin beta =

If sin alpha+sin beta=a and cos alpha-cos beta=b then tan((alpha-beta)/2) is equal to-

If tan alpha and tan beta are the roots of x^2 + ax +b =0 then (sin(alpha+beta))/(sin alpha sin beta) is equal to

If sin alpha+sin beta=a and cos alpha+cos beta=b then tan((alpha-beta)/(2)) is equal to

If cos alpha + cos beta =0 = sin alpha + sin beta , then cos 2 alpha + cos 2 beta is equal to

If alpha, beta are solutions of a cos theta + b sin theta = c where a, b, c in R and a^(2) + b^(2) gt 0, cos alpha ne cos beta, sin alpha ne sin beta then prove that sin alpha sin beta = (c^(2)-a^(2))/(a^(2) + b^(2))