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The correct Answer is:
RD SHARMA-बीजीय सर्वसमिकाएँ -बहु विकल्पीय प्रश्न
- यदि x+1/x=5 , तो x^(2) +1/(x^(2)
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- यदि x+1/x=2 , तो x^(3) +1/(x^(3))=
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- यदि x+1/x=4 , तो x^(4) + 1/(x^(4)) =
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- यदि x+1/x=3 , तो x^(6) +1/(x^(6))=
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- यदि x^(4)+1/(x^(4))=623 , तो x+1/x =
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- यदि x^(2) +1/(x^(2))=102 , तो x- 1/x=
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- यदि x^(3) +1/(x^(3))=110 , तो x+1/x=
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- यदि x^(3)-1/(x^(3)) =14 , तो x-1/x
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- यदि x^(4) +1/(x^(4))=194 , तो x^(3)+1/(x^(3))=
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- यदि x-1/x=15/4 , तो x+1/x =
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- यदि 3x+2/x=7 , तो (9x^(2)-4/(x^(2)))=
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- यदि a^(2) +b^(2)+c^(2)-ab-bc-ca=0 , तो
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- यदि a+b+c=0 , तो (a^(2))/(bc)+(b^(2))/(ca) +(c^(2))/(ab)=
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- यदि a^(1/3) +b^(1/3) +c^(1/3)=0 , तो
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- यदि a+b+c=9 , तो ab+bc+ca=23 तो a^(2) + b^(2) +c^(2)
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- यदि a+b+c = 9 , तथा ab+bc +ca = 23 तथा a^(3) + b^(3) +c^(3) - 3ab...
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- (a-b)^(3) +(b-c)^(3) +(c-a)^(3) =
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- ((a^(2)-b^(2))^(3)+(b^(2)-c^(2))^(3)+(c^(2)-a^(2))^(3))/((a-b)^(3)+(b-...
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- (a+b)(a-b)(a^(2)-ab+b^(2))(a^(2)+ab+b^(2))=
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- यदि a/b+b/a=-1 हो , तो a^(3) - b^(3) =
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